How many moles of water, $\mathrm { H } _ { 2 }$ O,are produced from the reaction of 16 grams methane,C $\mathrm { H } _ { 4 }$ ,with an unlimited supply of oxygen, $\mathrm { O } _ { 2 }$ .How many grams of $\mathrm { H } _ { 2 }$ O is this? C $\mathrm { H } _ { 4 }$ + 2 $\mathrm { O } _ { 2 }$ ? C $\mathrm { O } _ { 2 }$ + 2 $\mathrm { H } _ { 2 }$ O
A)0.889 mole,which is 16 grams
B)2.0 moles of water,which is 32 grams
C)2.0 moles of water,which is 36 grams
D)1.0 mole of water,which is 18 grams

Question

Quizplus · Accepted Answer

16 grams of CH4 is 1 mole (molar mass = 16 g/mol). The balanced equation shows 1 mole of CH4 produces 2 moles of H2O. Thus, 2 moles of H2O are produced, which is 36 grams (molar mass of H2O = 18 g/mol).

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