In the Oxidation-Reduction Reaction Mg(s) $\mathrm { Cu } ^ { 2 + }$

In the oxidation-reduction reaction Mg(s) + $\mathrm { Cu } ^ { 2 + }$ (aq) ? 3 $\mathrm { Mg } ^ { 2 + }$ (aq) + Cu(s) ,which atom or ion is reduced? Which atom or ion is oxidized?

A) The $\mathrm { Cu } ^ { 2 + }$ ion is oxidized as it gains electrons from the copper metal,Cu.The magnesium metal,Mg,is reduced as it loses electrons to form $\mathrm { Mg } ^ { 2 + }$ .
B) The $\mathrm { Mg } ^ { 2 + }$ ion is reduced as it gains electrons from the copper metal,Cu.The $\mathrm { Cu } ^ { 2 + }$ is oxidized as it loses electrons to the $\mathrm { Mg } ^ { 2 + }$ .
C) The $\mathrm { Cu } ^ { 2 + }$ ion is reduced as it gains electrons to form copper metal,Cu.The magnesium metal,Mg,is oxidized as it loses electrons to form $\mathrm { Mg } ^ { 2 + }$ .
D) Since Mg goes from a solid to an aqueous solution and Cu goes from an aqueous solution to a solid,an oxidation-reduction reaction did not occur.