A sample of 500 students is selected from a known population of 15,000 students to construct a 99% confidence interval for the average SAT score. What correction factor should be used to compute the standard error?
A)0.9499
B)0.9832
C)2.5760
D)Cannot be determined

Question

Quizplus · Accepted Answer

The correction factor for standard error in this case is sqrt((N-n)/(N-1)), where N is the population size and n is the sample size. Therefore, the correction factor in this case would be sqrt((15000-500)/(15000-1)) = 0.9832. The other choices are not relevant for this calculation.

A Sample of 500 Students Is Selected from a Known