___________ g of sucrose (molecular weight = 342g)would be added to 1L of water to produce a 2.5 Osm solution.
A)342
B)500
C)855
D)2.5

Question

Quizplus · Accepted Answer

First, we need to understand what is meant by a 2.5 Osm solution.

Osmolarity is a measure of the concentration of solute particles (ions or molecules) in a solution. 1 osmol/L (Osm) refers to a solution that contains 1 mole of solute particles per liter of solution.

To calculate the number of moles of sucrose needed to make a 2.5 Osm solution:

2.5 Osm/L = 2.5 moles of solute/L of solution

Therefore, we need 2.5 moles of sucrose per liter of solution.

To convert moles to grams, we need to multiply by the molecular weight of sucrose.

2.5 moles x 342 g/mol = 855 g

Therefore, 855 g of sucrose would need to be added to 1 L of water to produce a 2.5 Osm solution.

The correct answer is C) 855.

___________ G of Sucrose (Molecular Weight = 342g)would Be Added