One mole of solute per liter depresses the freezing point of water by -1.86 ^ C.

Question

Quizplus · Accepted Answer

This statement is true according to Raoult's Law, which states that the freezing point depression (ΔTf) of a solvent is directly proportional to the molality (moles of solute per kilogram of solvent) of the solute particles in the solution. For water, the freezing point depression constant (Kf) is -1.86°C/m, which corresponds to -1.86°F/m. Therefore, one mole of solute per liter (or 1000 grams) of water would give a ΔTf of -1.86°C or -1.86°F.

One Mole of Solute Per Liter Depresses the Freezing Point