On a Sunday in April, dog bite victims arrive at Carver Memorial Hospital at a historical rate of 0.6 victim per day. On a given Sunday in April, what is the probability that exactly two dog bite victims will arrive?
A).0875
B).0902
C).0988
D).0919

Question

Quizplus · Accepted Answer

The probability of exactly two dog bite victims arriving at Carver Memorial Hospital on a given Sunday in April, when the historical rate is 0.6 victim per day, can be calculated using the Poisson distribution formula: P(x; μ) = (e^(-μ) * μ^x) / x!, where μ is the average rate (0.6 in this case), x is the number of occurrences (2 victims), and e is the base of the natural logarithm (approximately 2.71828). Plugging in the values gives P(2; 0.6) = (e^(-0.6) * 0.6^2) / 2! = (0.5488 * 0.36) / 2 = 0.0988.

On a Sunday in April, Dog Bite Victims Arrive at Carver