If each nuclear fission reaction in a nuclear power plant releases 173 MeV (1 MeV = 1.6 $\times$ 10^-13J),what quantity of Uranium-235 must be consumed each day to keep a 350MW plant producing at capacity? Assume the power plant is 35% efficient.

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The Answer of If each nuclear fission reaction in a nuclear power plant releases 173 MeV (1 MeV = 1.6 $\times$ 10^-13J),what quantity of Uranium-235 must be consumed each day to keep a 350MW plant producing at capacity? Assume the power plant is 35% efficient.

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