A baseball has a mass of 0.15 kg.If pitched at 40.0 m/s with a relative uncertainty of 1%,how uncertain is its position? A) 9.1 $\times$ 10^-34 m B) 5.7 $\times$ 10^-34 m C) 1.8 $\times$ 10^-34 m D) 6.3 $\times$ 10^-33 m

Question

Quizplus · Accepted Answer

The uncertainty in position is given by the Heisenberg uncertainty principle: ΔxΔp ≥ h/4π, where Δx is the uncertainty in position, Δp is the uncertainty in momentum, and h is Planck's constant. The uncertainty in momentum is given by the product of the mass and the uncertainty in velocity: Δp = mΔv. Substituting these expressions into the Heisenberg uncertainty principle, we get: ΔxΔv ≥ h/4πm. Solving for Δx, we get: Δx ≥ h/4πmΔv. Plugging in the given values, we get: Δx ≥ (6.626 × 10^-34 J s)/(4π × 0.15 kg × 40.0 m/s × 0.01) = 9.1 × 10^-34 m.

A Baseball Has a Mass of 0 ×\times× 10-34 M B) 5

A Baseball Has a Mass of 0 $\times$ 10^-34 M
B) 5