Light of wavelength 400 nm bombards a surface with work function 2.46 eV. What is the maximum kinetic energy of the photoelectrons from this surface?
A) no photoelectrons are emitted
B) 2.46 eV
C) 3.30 eV
D) 0.640 eV
E) 0.840 eV

Question

Quizplus · Accepted Answer

The energy of the incident photons can be calculated using the formula E = hc/λ, where h is Planck's constant (4.135667696 x 10^-15 eV·s), c is the speed of light (3 x 10^8 m/s), and λ is the wavelength (400 nm = 400 x 10^-9 m). This gives E ≈ 3.10 eV. The maximum kinetic energy of the photoelectrons is given by the difference between the photon energy and the work function: KE_max = E - work function = 3.10 eV - 2.46 eV = 0.640 eV.

Light of Wavelength 400 Nm Bombards a Surface with Work