In a single-slit experiment,light of wavelength 500 nm is used to produce a diffraction pattern on a screen 4.0 m away.If the distance between both 3^rd order minima is 6.0 cm,what is the slit width? A) 2.0 $\times$ 10^-4 m B) 1.0 $\times$ 10^-4 m C) 4.0 $\times$ 10^-4 m D) 0.67 $\times$ 10^-4 m E) 0.44 $\times$ 10^-4 m

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Quizplus · Accepted Answer

The distance between the 3rd order minima is given by:$$d\sin	heta=3\lambda$$where d is the slit width, 	heta is the angle of diffraction, and \lambda is the wavelength of light.We can use the small angle approximation to get:$$	an	heta=\frac{y}{L}$$where y is the distance from the central maximum to the 3rd order minima and L is the distance from the slit to the screen.Substituting this into the first equation, we get:$$d\frac{y}{L}=3\lambda$$Solving for d, we get:$$d=\frac{3\lambda L}{y}$$Plugging in the given values, we get:$$d=\frac{3(500	imes10^{-9}	ext{ m})(4.0	ext{ m})}{0.060	ext{ m}}=1.0	imes10^{-4}	ext{ m}$$

In a Single-Slit Experiment,light of Wavelength 500 Nm Is Used ×\times×

In a Single-Slit Experiment,light of Wavelength 500 Nm Is Used $\times$