Decreasing the focal length of the eyepiece in a compound microscope by 50% changes the magnification to _______ times the previous magnification.
A) 0.50
B) 1.5
C) 1.7
D) 2.0
E) 4.0

Question

Quizplus · Accepted Answer

According to the formula for compound microscope magnification (M = f_obj/f_eyepiece), decreasing the focal length of the eyepiece by 50% means that the denominator (f_eyepiece) is now doubled. Therefore, the magnification (M) is now multiplied by 2, which gives a magnification that is 2 times greater than the previous magnification. So the correct answer is D) 2.0.

Decreasing the Focal Length of the Eyepiece in a Compound