A small object is enclosed in plastic (n = 1.5). The object appears to be 4.0 cm below the surface.What is the actual distance of the object below the surface?
A) 2.0 cm
B) 2.7 cm
C) 4.0 cm
D) 5.5 cm
E) 6.0 cm

Question

Quizplus · Accepted Answer

The apparent depth (4.0 cm) is related to the actual depth by the refractive index (n = 1.5) using the formula: apparent depth = actual depth / n. Solving for actual depth gives: actual depth = apparent depth * n = 4.0 cm * 1.5 = 6.0 cm.

A Small Object Is Enclosed in Plastic (N = 1