A 33 mH inductor has a current going through it that is increasing at a rate of 2.3 A/s. What is the magnitude of the induced emf in this coil?
A) 33 mV
B) 76 mV
C) 13 mV
D) 95 mV
E) 2.5 V

Question

Quizplus · Accepted Answer

The magnitude of the induced emf in the coil can be calculated using Faraday's law of electromagnetic induction, which states that the induced emf (ε) in a coil is equal to the negative rate of change of magnetic flux through the coil. For an inductor, this can be simplified to ε = L(di/dt), where L is the inductance in henries (H) and di/dt is the rate of change of current in amperes per second (A/s). Plugging in the given values, ε = 0.033 H * 2.3 A/s = 0.0759 V, or approximately 76 mV.

A 33 MH Inductor Has a Current Going Through It