A proton cyclotron has a magnetic field of 0.20 T between its poles and a radius of 0.40 m.What is the maximum energy for the protons from this machine? A) 1.6 $\times$ 10^-13 J B) 3.2 $\times$ 10^-13 J C) 4.9 $\times$ 10^-13 J D) 3.2 $\times$ 10^-14 J E) 4.9 $\times$ 10^-14 J

Question

Quizplus · Accepted Answer

The maximum energy for the protons from the cyclotron can be calculated using the formula: 
E = qV = (qBr)/2m 
where E is the maximum energy, q is the charge of the proton, V is the potential difference between the cyclotron poles, B is the magnetic field, r is the radius of the cyclotron, and m is the mass of the proton.

Plugging in the given values, we get: 
E = (1.602 x 10^-19 C)(0.20 T)(0.40 m)/(2(1.673 x 10^-27 kg)) 
E = 4.9 x 10^6 eV = 4.9 x 10^-14 J 
Converting to scientific notation with the correct SI prefix, we get: 
E = 4.9 fJ = 4.9 x 10^-15 J = 4.9 x 10^-14 J

Therefore, the correct answer is E (4.9 x 10^-14 J).

A Proton Cyclotron Has a Magnetic Field of 0 ×\times× 10-13 J B) 3

A Proton Cyclotron Has a Magnetic Field of 0 $\times$ 10^-13 J
B) 3