A 300 T urn coil of area 25 cm² is placed in an 80 mT magnetic field.If the coil carries a current of 3.3 A,what is the magnitude of the maximum magnetic torque it could experience?

Question

Quizplus · Accepted Answer

The magnetic torque experienced by a current-carrying coil is given by:
τ = NIABsinθ

where N is the number of turns, I is the current, A is the area of the coil, B is the magnetic field strength, and θ is the angle between the direction of the magnetic field and the normal to the plane of the coil.

In this case, N=300, A=25 cm^2 = 0.0025 m^2, B=80 mT = 0.08 T, I=3.3 A, and θ=90° (since the coil is perpendicular to the magnetic field).

Substituting these values, we get:
τ = (300)(3.3)(0.0025)(0.08)sin90° = 0.20 N·m

Therefore, the maximum magnetic torque experienced by the coil is 0.20 N·m, which is answer choice D.

A 300 T Urn Coil of Area 25 Cm2 Is

A 300 T Urn Coil of Area 25 Cm² Is