The magnetic field inside a solenoid having 100 turns per cm at a current of 5.0 A is A) 2.0 $\times$ 10^-2 T. B) 1.0 $\times$ 10^-2 T. C) 1.0 $\times$ 10^-4 T. D) 6.3 $\times$ 10^-4 T. E) 6.3 $\times$ 10^-2 T.

Question

Quizplus · Accepted Answer

The magnetic field inside a solenoid can be calculated using the formula: B = μ₀nI where μ₀ is the permeability of free space, n is the number of turns per unit length of the solenoid, and I is the current. Substituting the given values, we get: B = (4π × 10⁻⁷ T m/A) × (100 turns/cm × 10⁴ cm⁻¹) × 5.0 A B = 6.3 × 10⁻² T B = 6.3 × 10⁻² F1F1F1S1×F1F1F1010^-2 T Therefore, the best choice is (E) 6.3 F1F1F1S1×F1F1F1010^-2 T.

The Magnetic Field Inside a Solenoid Having 100 Turns Per ×\times×

The Magnetic Field Inside a Solenoid Having 100 Turns Per $\times$