A solenoid of radius 1.1 cm produces a magnetic field at its center is 0.28 T.What is the magnetic flux through the center of the solenoid? A) 1.1 $\times$ 10^-4 T·m² B) 2.2 $\times$ 10^-4 T·m² C) 3.3 $\times$ 10^-3 T·m² D) 2.2 $\times$ 10^-3 T·m² E) 3.3 $\times$ 10^-4 T·m²

Question

Quizplus · Accepted Answer

The magnetic flux through the center of the solenoid can be calculated using the formula, Φ = BA, where B is the magnetic field at the center of the solenoid and A is the area of the cross-section perpendicular to the direction of the magnetic field. Here, the radius of the solenoid is given as 1.1 cm, so the diameter is 2.2 cm. Therefore, the cross-sectional area is A = πr^2 = π(1.1 cm)^2 = 3.8013 cm^2 = 3.8013×10^(-4) m^2. Plugging in the values, we get Φ = (0.28 T)×(3.8013×10^(-4) m^2) = 1.06234×10^(-4) T·m^2 = 1.06234×10^(-4) Wb (Weber). Round this off to one decimal place to get the final answer as 1.1×10^(-4) Wb or 1.1×10^(-4) T·m^2. Therefore, the best choice is A.

A Solenoid of Radius 1 ×\times× 10-4 T·m2 B) 2 ×\times× 10-4 T·m2 C) 3

A Solenoid of Radius 1 $\times$ 10^-4 T·m²
B) 2 $\times$ 10^-4 T·m²
C) 3