A charged particle enters a region of magnetic field at a speed of 2.8 $\times$ 10⁴ m/s, at an angle of 37 degrees relative to the magnetic field direction.What will be the magnitude of the component of the particle's velocity that is parallel to the magnetic field while it is in this region? A) Insufficient information is given. B) 2.2 $\times$ 10⁴ m/s C) 2.1 $\times$ 10⁴ m/s D) 1.7 $\times$ 10⁴ m/s E) 2.8 $\times$ 10⁴ m/s

Question

Quizplus · Accepted Answer

The component of the particle's velocity that is parallel to the magnetic field is given by v|| = v * cos(theta), where v is the speed of the particle and theta is the angle between the velocity vector and the magnetic field direction. In this case, v = 2.8 x 10^4 m/s and theta = 37 degrees, so v|| = 2.8 x 10^4 m/s * cos(37 degrees) = 2.2 x 10^4 m/s.

A Charged Particle Enters a Region of Magnetic Field at a Speed