A flashlight, which uses two 1.5 V batteries in series, is turned on for 2.0 minutes. If the current in the flashlight is 100 mA, what is the energy dissipated?
A) 12 J
B) 9.0 J
C) 72 J
D) 36 J
E) 18 J

Question

Quizplus · Accepted Answer

The energy dissipated can be calculated using the formula:

Energy (E) = Power (P) x Time (t)

We can first calculate the power of the flashlight:

Power = Voltage x Current

The voltage of two 1.5 V batteries in series is 3 V. Therefore:

Power = 3 V x 100 mA = 0.3 W

Now, we can calculate the energy dissipated:

E = P x t = 0.3 W x 2.0 min x 60 s/min = 36 J

Therefore, the answer is D.

A Flashlight, Which Uses Two 1