A 3.6 $\mu$C charge is moved from a position where its electric potential energy is 7.2 my to a position where its potential energy is 1.8 my.What is the potential at the first position?

Question

Quizplus · Accepted Answer

We know that the electric potential energy (PE) of a charge (q) in an electric field (E) is given by:
PE = q * potential difference

Therefore, we can write:

q * (V2 - V1) = PE
where V1 is the potential at the initial position and V2 is the potential at the final position.

Substituting the given values, we get:

(3.6 x 10^-6 C) * (1.8 x 10^6 V - V1) = 7.2 x 10^-6 J

Simplifying this equation, we get:

V1 = 2000 V

Therefore, the answer is (B).

A 36 μ\muμ C Charge Is Moved from a Position Where Its Electric

A 36 $\mu$ C Charge Is Moved from a Position Where Its Electric