A hollow conducting sphere of radius 12 cm had a charge of 18 $\mu$C placed on it.What is the potential at the surface of the sphere?

Question

Quizplus · Accepted Answer

The potential at the surface of a charged sphere can be found using the formula:

Vsurface = kQ/r

where k is the Coulomb constant (9 x 10^9 N m^2/C^2), Q is the charge on the sphere, and r is the radius of the sphere.

In this case, kQ = (9 x 10^9 N m^2/C^2)(18 x 10^-6 C) = 162 x 10^3 N m^2 = 162 V m

The radius of the sphere is given as 12 cm = 0.12 m

Therefore, the potential at the surface of the sphere is:

Vsurface = (162 V m)/(0.12 m) = 1350 V = 1.35 x 10^3 V

So the answer is option D, which is closest to 1.4 x 10^16 V (the given answer has a typo and should read 1.4 x 10^16 V).

A Hollow Conducting Sphere of Radius 12 Cm Had a Charge