A parallel plate capacitor with an air dielectric is attached to a voltage source and charged.The voltage source is removed,and then the plates are separated to double their previous distance.What happens to the energy stored by the capacitor when the plates are separated?

Question

Quizplus · Accepted Answer

When the plates are separated, the capacitance decreases, and since the charge remains constant (as the voltage source is removed), the energy stored in the capacitor, which is proportional to the square of the charge divided by the capacitance, doubles.

A Parallel Plate Capacitor with an Air Dielectric Is Attached