An electron is fired through a pair of deflection plates,which produce a 2.00 cm long region with an electric field of 4000 N/C perpendicular to the electron's initial velocity.If the initial speed of the electron is 1.00 $\times$ 10⁷ m/s,what is its new component of velocity after going through the deflection plates? A) 2.0 $\times$ 10⁷ m/s B) 7.1 $\times$ 10⁶ m/s C) 2.8 $\times$ 10⁶ m/s D) 1.4 $\times$ 10⁶ m/s E) 6.5 $\times$ 10⁴ m/s

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Quizplus · Accepted Answer

The force on the electron due to the electric field is F = eE, where e is the charge of the electron. This force causes an acceleration a = F/m = eE/m. The time t the electron spends in the field is the length of the plates divided by its initial speed, t = 0.02 m / (1.00 * 10^7 m/s). The change in velocity is Δv = at = (eE/m) * t. Substituting the values, the new component of velocity is approximately 1.4 * 10^6 m/s.

An Electron Is Fired Through a Pair of Deflection Plates,which ×\times×

An Electron Is Fired Through a Pair of Deflection Plates,which $\times$