A conducting sphere of radius 10.0 cm holds a net charge of 4.4 $ \mu$C.What is the surface charge density? A) 0.0 B) 3.5 $\times$ 10^-5 C/m² C) 1.1 $\times$ 10^-5 C/m² D) 2.2 $\times$ 10^-4 C/m² E) 5.6 $\times$ 10^-3 C/m²

Question

Quizplus · Accepted Answer

The surface charge density is given by the formula σ = Q/4πr^2, where Q is the net charge and r is the radius of the sphere. Plugging in the given values, we get σ = (4.4 µC)/(4π(0.1 m)^2) = 3.5 * 10^-5 C/m^2.

A Conducting Sphere of Radius 10 μ \muμ CWhat Is the Surface Charge Density? A) 0

A Conducting Sphere of Radius 10 $\mu$ CWhat Is the Surface Charge Density?
A) 0