Using 0.0200 mol of an ideal monatomic gas,an isochoric process from A (230 kPa,1.00 L)to B (98 kPa,1.00 L)results in what change in internal energy?
A) -200 J
B) +200 J
C) -375 J
D) +375 J

Question

Quizplus · Accepted Answer

The change in internal energy for an ideal monatomic gas is given by ΔU = (3/2)nRΔT. Since the process is isochoric (constant volume), the change in pressure directly relates to the change in temperature. Using the ideal gas law, the change in temperature can be calculated, and subsequently, the change in internal energy. The calculation results in a decrease of approximately 200 J.

Using 00200 Mol of an Ideal Monatomic Gas,an Isochoric Process from from a (230