A refrigerator uses 40.0 J of work to extract 90.0 J from a heat reservoir at 0.00$^{\circ}$C.What is the coefficient of performance for the refrigerator?
A) 1.60
B) 2.05
C) 2.25
D) 2.85

Question

Quizplus · Accepted Answer

The coefficient of performance (COP) for a refrigerator is calculated using the formula COP = Qc/W, where Qc is the heat extracted from the cold reservoir and W is the work done. Here, COP = 90.0 J / 40.0 J = 2.25.

A Refrigerator Uses 40 ∘^{\circ}∘ CWhat Is the Coefficient of Performance for the Refrigerator? A)

A Refrigerator Uses 40 $^{\circ}$ CWhat Is the Coefficient of Performance for the Refrigerator?
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