When 2.000 kg of water evaporates,22.60 $\times$ 10⁵ J/kg of heat are needed.What is the entropy change in the boiling process?

Question

Quizplus · Accepted Answer

The entropy change (ΔS) can be calculated using the formula ΔS = Q/T, where Q is the heat absorbed and T is the temperature in Kelvin. Here, Q = 2.000 kg * 22.60 * 10^5 J/kg = 45.2 * 10^5 J. Assuming the boiling point of water is 373 K, ΔS = 45.2 * 10^5 J / 373 K = 12,120 J/K.

When 2000 Kg of Water Evaporates,22 ×\times× 105 J/kg of Heat Are Needed

When 2000 Kg of Water Evaporates,22 $\times$ 10⁵ J/kg of Heat Are Needed