It can be shown that the change in entropy in heating or cooling a sample is given by the relation $\Delta$S = mc ln (T_F/T_i),where m is the mass of the sample,c is the specific heat of the sample,and T_F and T_i are the final and initial temperatures respectively.What is the change in entropy when 10.0 grams of lead with a specific heat of 0.452 J/gm K is heated from 10.0$^{\circ}$C to 50.0$^{\circ}$C? A) 0.45 J/K B) 0.60 J/K C) 0.90 J/K D) 0.30 J/K

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The Answer of It can be shown that the change in entropy in heating or cooling a sample is given by the relation $\Delta$S = mc ln (T_F/T_i),where m is the mass of the sample,c is the specific heat of the sample,and T_F and T_i are the final and initial temperatures respectively.What is the change in entropy when 10.0 grams of lead with a specific heat of 0.452 J/gm K is heated from 10.0$^{\circ}$C to 50.0$^{\circ}$C? A) 0.45 J/K B) 0.60 J/K C) 0.90 J/K D) 0.30 J/K

It Can Be Shown That the Change in Entropy in Heating