1.50 moles of an ideal gas freely expands from 1.00 liter to 4.50 liters.The change in entropy in the expansion is

Question

Quizplus · Accepted Answer

The change in entropy of an ideal gas during an irreversible process is given by:

ΔS = nR ln(Vf/Vi)

where n is the number of moles, R is the gas constant, Vi is the initial volume and Vf is the final volume.

Substituting the given values, we get:

ΔS = (1.50 mol)(8.31 J/mol·K) ln(4.50 L/1.00 L)
ΔS = 16.3 J/K

Therefore, the correct answer is C.

150 Moles of an Ideal Gas Freely Expands from 1