One mole of an ideal gas has a volume of 0.0224 m³ and a pressure of 101.3 $\times$ 10³ Pa.What is the absolute temperature of the gas? A) 273 K B) 325 K C) 346 K D) 352 K E) 376 K

Question

Quizplus · Accepted Answer

The ideal gas law is PV = nRT. For one mole (n=1) of an ideal gas, P = 101.3 * 10^3 Pa, V = 0.0224 m^3, and R = 8.314 J/(mol·K). Solving for T gives T = PV/R = (101.3 * 10^3 * 0.0224) / 8.314 = 273 K.

One Mole of an Ideal Gas Has a Volume of 0.0224