The diffusion constant for water in air is 2.4 $\times$ 10^-5 m²/s.What is the distance a water molecule can travel by diffusion in 10min? A) 17 cm B) 20 cm C) 25 cm D) 31 cm E) 36 cm

Question

Quizplus · Accepted Answer

The distance a molecule can travel by diffusion is given by the formula: distance = sqrt(2 * D * t), where D is the diffusion constant and t is the time in seconds. For 10 minutes (600 seconds), the distance is sqrt(2 * 2.4 * 10^-5 m^2/s * 600 s) = 0.17 m or 17 cm.

The Diffusion Constant for Water in Air Is 2 ×\times× 10-5 M2/s

The Diffusion Constant for Water in Air Is 2 $\times$ 10^-5 M²/s