The diffusion constant for water in air is 2.4 $\times$ 10^-5 m²/s.How long would it take a water molecule to diffuse a distance of 10.0 meters? A) 400 hours B) 450 hours C) 500 hours D) 580 hours E) 600 hours

Question

Quizplus · Accepted Answer

The distance diffused (x) can be calculated using the formula:

x = sqrt(2Dt)

where D is the diffusion constant, t is time, and sqrt is the square root.

Rearranging the formula to solve for t:

t = x^2 / (2D)

Plugging in the given values:

D = 2.4 x 10^-5 m^2/s
x = 10.0 m

t = (10.0 m)^2 / (2 x 2.4 x 10^-5 m^2/s)
t ≈ 583.33 s ≈ 9.7 minutes

Therefore, the answer is approximately 580 hours (or 24.2 days).

The Diffusion Constant for Water in Air Is 2 ×\times× 10-5 M2/s

The Diffusion Constant for Water in Air Is 2 $\times$ 10^-5 M²/s