A 50.00 ml sample of mercury at room temperature (293.0 K) is cooled.What is the volume of the sample when the mercury reaches 273.0 K? The coefficient of volume expansion of mercury is 182.0 $\times$ 10^-6 K^-1. A) 49.39 ml B) 49.94 ml C) 49.82 ml D) 48.18 ml E) 49.96 ml

Question

Quizplus · Accepted Answer

We can use the formula for volume expansion:

ΔV = V0βΔT

where 
ΔV = change in volume 
V0 = initial volume 
β = coefficient of volume expansion 
ΔT = change in temperature

We can solve for the final volume (Vf) by rearranging the formula:

Vf = V0 + ΔV 
   = V0 + V0βΔT 
   = V0 (1 + βΔT)

Plugging in the given values:

V0 = 50.00 ml 
β = 182.0 x 10^-6 / K 
ΔT = 293.0 K - 273.0 K = 20 K

Vf = 50.00 ml (1 + 182.0 x 10^-6 / K * 20 K) 
   = 49.82 ml

Therefore, the best choice is C.

A 5000 Ml Sample of Mercury at Room Temperature (293 ×\times×

A 5000 Ml Sample of Mercury at Room Temperature (293 $\times$