The mass density of pure water is 1000 kg/m³.If the molecular mass of water is 18.0 u,how many water molecules are in spherical water balloon of radius 1.0 cm?

Question

Quizplus · Accepted Answer

First, we need to calculate the volume of the spherical water balloon:

V = (4/3)πr^3 = (4/3)π(0.01 m)^3 = 4.19×10^-6 m^3

Next, we can use the mass density and molecular mass of water to calculate the number of water molecules:

1. Calculate the mass of water in the spherical balloon:

m = ρV = 1000 kg/m^3 × 4.19×10^-6 m^3 = 4.19×10^-3 kg

2. Calculate the number of moles of water:

n = m/M = 4.19×10^-3 kg / 18.0 g/mol = 0.000232 moles

3. Finally, use Avogadro's number to calculate the number of water molecules:

N = n × N_A = 0.000232 mol × 6.022×10^23 mol^-1 = 1.40×10^20

Therefore, the answer is C) 1.4 x 10^20.

The Mass Density of Pure Water Is 1000 Kg/m3 ×\times× 1023 B) 2

The Mass Density of Pure Water Is 1000 Kg/m³ $\times$ 10²³
B) 2