A 30.0 cm long brass rod is suspended at the ends by long strings.The rod is struck at one end parallel to the rod and causes the rod to vibrate longitudinally with the ends free.(Y = 9.00 $\times$ 10¹⁰ N/m², S = 3.50 $\times$ 10¹⁰ N/m², B = 6.70 $\times$ 10¹⁰ N/m²,density = 8,470 kg/m³)The frequency of the vibration is

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The frequency of longitudinal vibrations for a rod with free ends is given by $ f = \frac{n}{2L} \sqrt{\frac{Y}{\rho}} $, where $ n $ is the mode number, $ L $ is the length, $ Y $ is Young's modulus, and $ \rho $ is the density. For the fundamental frequency (n=1), substituting the given values, the frequency is approximately 5,430 Hz.

A 300 Cm Long Brass Rod Is Suspended at the Ends