A string with a length of 2.50 m has a mass of 5.00 gm.The velocity of wave propagation along the string is 210 m/s.The tension of the stretched string is
A) 88.2 N.
B) 75.0 N.
C) 70.2 N.
D) 66.7 N.
E) 60.2 N.

Question

Quizplus · Accepted Answer

The tension in the string can be calculated using the formula $ v = \sqrt{\frac{T}{\mu}} $, where $ v $ is the wave velocity, $ T $ is the tension, and $ \mu $ is the linear mass density ($\mu = \frac{mass}{length}$). Here, $\mu = \frac{5.00 \, \text{gm}}{2.50 \, \text{m}} = 0.002 \, \text{kg/m}$. Solving for $ T $, we get $ T = v^2 \times \mu = (210 \, \text{m/s})^2 \times 0.002 \, \text{kg/m} = 88.2 \, \text{N} $.

A String with a Length of 2