A string on a guitar is stretched between two points 35.0 cm apart with a tension of 65.0 N. The mass/length of the string is 0.00400 kg/m. The frequency of the mode of vibration with the lowest frequency is
A) 315 Hz.
B) 276 Hz.
C) 250 Hz.
D) 205 Hz.
E) 182 Hz.

Question

Quizplus · Accepted Answer

The fundamental frequency (lowest frequency) of a string fixed at both ends is given by the formula f = (1/2L) * sqrt(T/μ), where L is the length of the string, T is the tension, and μ is the mass per unit length. Substituting the given values: L = 0.35 m, T = 65.0 N, μ = 0.00400 kg/m, we find f = (1/2*0.35) * sqrt(65/0.004) = 182 Hz.

A String on a Guitar Is Stretched Between Two Points