A force of 15.0 N is applied to a wire with a diameter of 2.00 mm.If the wire changed length by 1.20 mm,then the stress in the wire is A) 4.77 $\times$ 10⁶ N/m². B) 5.38 $\times$ 10⁶ N/m². C) 6.73 $\times$ 10⁶ N/m². D) 7.27 $\times$ 10⁶ N/m². E) 8.75 $\times$ 10⁶ N/m².

Question

Quizplus · Accepted Answer

Stress is calculated as force divided by area. The area of the wire is π*(d/2)^2, where d is the diameter. Substituting the given values, the stress is 4.77 * 10^6 N/m^2.

A Force of 15 ×\times× 106 N/m2 ×\times× 106 N/m2 ×\times× 106 N/m2 ×\times×

A Force of 15 $\times$ 10⁶ N/m² $\times$ 10⁶ N/m² $\times$ 10⁶ N/m² $\times$