A hydraulic lift has a small piston with a diameter 5.0 cm piston and the large piston with a diameter of 25 cm.What force must be applied on the small piston in order to lift a car on the large piston that weighs 13,000 N?

Question

Quizplus · Accepted Answer

Using Pascal's principle, the force applied on the small piston is proportional to the area ratio of the pistons. The area ratio is (25/5)^2 = 25. Therefore, the force needed is 13,000 N / 25 = 520 N.

A Hydraulic Lift Has a Small Piston with a Diameter