A 1.10 kg hollow steel ball is submerged in water.It weighs in water 8.75 N.The volume of the cavity inside the ball is (density of steel is 7,900 kg/m³)

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Quizplus · Accepted Answer

The correct answer is A.The volume of the cavity inside the ball is 0.000168 m3.The weight of the ball in water is equal to the weight of the water displaced by the ball. The weight of the water displaced by the ball is equal to the volume of the water displaced by the ball multiplied by the density of water. The volume of the water displaced by the ball is equal to the volume of the ball minus the volume of the cavity inside the ball. The volume of the ball is equal to the mass of the ball divided by the density of steel. The density of steel is 7,900 kg/m3. The mass of the ball is 1.10 kg. The volume of the ball is 1.10 kg / 7,900 kg/m3 = 0.000139 m3. The volume of the cavity inside the ball is 0.000139 m3 - 0.000168 m3 = 0.000168 m3.

A 110 Kg Hollow Steel Ball Is Submerged in Water