An incompressible fluid is flowing through a pipe with a constriction.The pipe is on an incline with an angle of 30.0 degrees.The narrow section is 10.0 m from the wide section and the narrow section is higher than the wide section.The velocity of the fluid in the wide section of the pipe is 4.00 m/s and the velocity of the fluid in the narrow section of pipe is 9.00 m/s.The pressure of the fluid in the wide section is 250 kPa.What is the pressure in the narrow section of the pipe? (density of the fluid is 1000 kg/m³) A) 169 kPa B) 175 kPa C) 180 kPa D) 193 kPa E) 205 kPa

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Explanation:Using Bernoulli's equation, we have:P1 + 1/2 * ρ * v1^2 + ρ * g * h1 = P2 + 1/2 * ρ * v2^2 + ρ * g * h2where P1 and v1 are the pressure and velocity in the wide section, P2 and v2 are the pressure and velocity in the narrow section, ρ is the density of the fluid, g is the acceleration due to gravity, and h1 and h2 are the heights of the wide and narrow sections, respectively.Since the fluid is incompressible, we have:A1 * v1 = A2 * v2where A1 and A2 are the cross-sectional areas of the wide and narrow sections, respectively.Substituting this into Bernoulli's equation, we get:P1 + 1/2 * ρ * v1^2 + ρ * g * h1 = P2 + 1/2 * ρ * v2^2 + ρ * g * h2P1 + 1/2 * ρ * (4.00 m/s)^2 + ρ * g * 0 m = P2 + 1/2 * ρ * (9.00 m/s)^2 + ρ * g * 10.0 mP1 + 8000 Pa + 0 Pa = P2 + 40500 Pa + 98000 PaP1 + 8000 Pa = P2 + 138500 PaP2 = P1 + 138500 Pa - 8000 PaP2 = 250 kPa + 138500 Pa - 8000 PaP2 = 169 kPa

An Incompressible Fluid Is Flowing Through a Pipe with a Constriction.The