The surface tension of soapy water is 0.0250 N/m. What is the height of the water in a capillary tube of diameter 2.00 mm?
A) 5.10 mm
B) 4.77 mm
C) 4.21 mm
D) 3.98 mm
E) 3.66 mm

Question

Quizplus · Accepted Answer

The height of the water in the capillary tube is given by the equation:h = (2 * surface tension * cos(theta)) / (density * gravity * radius)where:h is the height of the water in the capillary tubesurface tension is the surface tension of the watertheta is the contact angle between the water and the capillary tubedensity is the density of the watergravity is the acceleration due to gravityradius is the radius of the capillary tubeIn this problem, we are given the following information:surface tension = 0.0250 N/mdiameter = 2.00 mmradius = 1.00 mmdensity = 1000 kg/m^3gravity = 9.81 m/s^2theta = 0 degrees (assuming the water wets the capillary tube)Plugging these values into the equation, we get:h = (2 * 0.0250 N/m * cos(0 degrees)) / (1000 kg/m^3 * 9.81 m/s^2 * 1.00 mm)h = 0.00510 mh = 5.10 mmTherefore, the height of the water in the capillary tube is 5.10 mm.

The Surface Tension of Soapy Water Is 0