A 250 g sticky hockey puck slides along a frictionless,horizontal ice surface at 75 m/s in the +x direction.It collides with a 500 g sticky puck originally sliding at 25 m/s in the -y direction.They collide totally inelastically.How much kinetic energy was lost in this collision?
A) 522 J
B) 779 J
C) 520 J
D) More information is needed

Question

Quizplus · Accepted Answer

The initial kinetic energy is calculated for both pucks and then the final kinetic energy is calculated after the collision. The difference gives the kinetic energy lost. Initial KE = 1/2 * 0.25 * 75^2 + 1/2 * 0.5 * 25^2 = 703.125 J. Final velocity is found using conservation of momentum, and final KE is 181.25 J. Energy lost = 703.125 - 181.25 = 521.875 J, approximately 522 J.

A 250 G Sticky Hockey Puck Slides Along a Frictionless,horizontal