A 200 N box is pushed up an incline that is 5.00 m long and rises 1 m.If the incline is frictionless,then the work done by the pushing force is
A) 336 J.
B) 305 J.
C) 275 J.
D) 200 J.
E) 157 J.

Question

Quizplus · Accepted Answer

The work done by a force is given by the formula: 
work = force x distance x cos(theta)

where force is the magnitude of the force applied, distance is the distance over which the force is applied, and theta is the angle between the force and the direction of motion.

In this case, the force applied is 200 N, the distance over which it is applied is 5.00 m, and the angle between the force and the direction of motion is 11.31 degrees (which can be found using the formula: tan(theta) = rise/run = 1/5, where rise = 1 m and run = 5 m).

Therefore, the work done by the pushing force is:
work = force x distance x cos(theta) = 200 N x 5.00 m x cos(11.31) = 200 J (rounded to the nearest whole number).

Hence, the best choice is D) 200 J.

A 200 N Box Is Pushed Up an Incline That