A spring is stretched from 0.500 m to 0.800 m. Assume the unstretched position is 0.00 m. If the spring constant of the spring is 10.0 N/m, what is the work done on the spring?
A) 1.95 J
B) 2.21 J
C) 2.45 J
D) 2.75 J
E) 3.01 J

Question

Quizplus · Accepted Answer

Work done on the spring is given by the formula: W = (1/2)kx^2, where k is the spring constant and x is the displacement from the equilibrium position. In this case, k = 10.0 N/m and x = 0.800 m - 0.500 m = 0.300 m. Therefore, W = (1/2)(10.0 N/m)(0.300 m)^2 = 1.95 J.

A Spring Is Stretched from 0