A 1.00 kg stone attached to a 1.00 m long string is traveling in a vertical circular orbit.What is the minimum tangential velocity at the top of the vertical circular orbit to keep the string from going slack?
A) 5.63 m/s
B) 5.31 m/s
C) 5.00 m/s
D) 4.50 m/s
E) 3.13 m/s

Question

Quizplus · Accepted Answer

The minimum tangential velocity at the top of the circle is found using the formula v = sqrt(g*r), where g is the acceleration due to gravity (9.81 m/s²) and r is the radius (1.00 m). This gives v = sqrt(9.81*1) = 3.13 m/s.

A 100 Kg Stone Attached to a 1