A 4,000 kg satellite is traveling in a circular orbit 200 km above the surface of the Earth.A 3.00 gram marble is dropped inside the satellite.What is the acceleration of the marble as viewed by the observers on the Earth? (Me = 5.98 $\times$ 10²⁴ kg,Re = 6.37 $\times$ 10⁶ m,G = 6.67 $\times$ 10^-11 N.m²/kg²) A) 9.80 m/s² B) 9.24 m/s² C) 8.90 m/s² D) 8.62 m/s² E) 7.95 m/s²

Question

Quizplus · Accepted Answer

The acceleration due to gravity at a height above the Earth's surface is given by g' = G * Me / (Re + h)^2. Substituting the given values, g' = 6.67 * 10^-11 * 5.98 * 10^24 / (6.37 * 10^6 + 200,000)^2 ≈ 9.24 m/s².

A 4,000 Kg Satellite Is Traveling in a Circular Orbit ×\times×

A 4,000 Kg Satellite Is Traveling in a Circular Orbit $\times$