A mouse is running away from a cat at 0.75 m/s and,at 1.25 m from his mouse hole,he accelerates at a constant rate of 0.25 m/s² until he reaches his hole safely.How long a time was required for him to cover the last 1.25 m? A) 1.4 s B) 1.7 s C) 1.2 s D) 10 s

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Quizplus · Accepted Answer

Using the equation of motion $ s = ut + \frac{1}{2}at^2 $, where $ s = 1.25 \, \text{m} $, $ u = 0.75 \, \text{m/s} $, and $ a = 0.25 \, \text{m/s}^2 $, we solve for $ t $ to find $ t \approx 1.4 \, \text{s} $.

A Mouse Is Running Away from a Cat at 0