An object with a mass of 200.0 kg is 500.0 Km above the surface of the earth.The force of gravity on the 200.0 kg mass is (G = 6.67 $\times$ 10^-11 N m²/kg²,radius of the earth is 6.38 $\times$ 10⁶ m,mass of earth is 5.98 $\times$ 10²⁴ kg) A) 2.02 $\times$ 10³ N. B) 1.69 $\times$ 10³ N. C) 1.42 $\times$ 10³ N. D) 1.28 $\times$ 10³ N. E) 1.05 $\times$ 10³ N.

Question

Quizplus · Accepted Answer

The force of gravity on an object is given by the equation F = (GMm)/r^2, where G is the gravitational constant, M is the mass of the planet, m is the mass of the object and r is the distance between the centers of mass. Plugging in the values given, we get F = (6.67x10^-11 N m^2/kg^2)(5.98x10^24 kg)(200 kg)/(6.38x10^6 m + 5x10^5 m)^2 = 1.69x10^13 N. Therefore, the best choice is B) 1.69x10^13 N, after converting to scientific notation.

An Object with a Mass of 200 ×\times× 10-11 N M2/kg2,radius of the Earth Is 6

An Object with a Mass of 200 $\times$ 10^-11 N M²/kg²,radius of the Earth Is 6