A mountain climber lies flat on the surface of a glacier that is inclined at 30 degrees below the horizontal.He remains stationary because he is holding onto a rope attached to a spike embedded in the ice further up slope than he is.The rope is parallel to the surface of the ice.If the force of the ice upon his body is 210N,what is the tension in the rope?

Question

Quizplus · Accepted Answer

The tension in the rope is equal to the component of the force of the ice upon the climber's body that is parallel to the surface of the ice. This component is given by:$$T = F \sin 	heta$$where:* T is the tension in the rope* F is the force of the ice upon the climber's body* θ is the angle of inclination of the glacierSubstituting the given values into this equation, we get:$$T = 210 N \sin 30^\circ = 105 N$$Therefore, the tension in the rope is 105 N.

A Mountain Climber Lies Flat on the Surface of a Glacier